RD Sharma class 10 solutions Chapter 8 Quadratic Equations Ex 8.3
RD Sharma Class 10 Solutions Quadratic Equations Exercise 8.3
Solve the following quadratic equations by factorization.
Question 1.
(x – 4) (x + 2) = 0
Solution:
(x – 4) (x + 2) = 0
Either x – 4 = 0, then x = 4
or x + 2, = 0, then x = -2
Roots are x = 4, -2
Question 2.
(2x + 3) (3x – 7) = 0
Solution:
Question 3.
3x
2
– 14x – 5 = 0 (C.B.S.E. 1999C)
Solution:
Roots are x = 5, \(\frac { -1 }{ 3 }\)
Question 4.
9x
2
– 3x – 2 = 0
Solution:
Question 5.
Solution:
Question 6.
6x
2
+ 11x + 3 = 0
Solution:
Question 7.
5x
2
– 3x – 2 = 0
Solution:
Question 8.
48x
2
– 13x – 1 =0
Solution:
Roots are x = \(\frac { 1 }{ 3 }\) , \(\frac { -1 }{ 16 }\)
Question 9.
3x
2
= – 11x – 10
Solution:
Question 10.
25x (x + 1) = -4
Solution:
Question 11.
16x – \(\frac { 10 }{ x }\) = 27 [CBSE 2014]
Solution:
Question 12.
Solution:
Question 13.
x – \(\frac { 1 }{ x }\) = 3, x ≠ 0 [NCERT, CBSE 2010]
Solution:
Question 14.
Solution:
Question 15.
Solution:
Question 16.
a
2
x
2
– 3abx + 2b
2
= 0
Solution:
Question 17.
9x
2
– 6b
2
x – (a
4
– b
4
) = 0 [CBSE 2015]
Solution:
Question 18.
4x
2
+ 4bx – (a
2
– b
2
) = 0
Solution:
Question 19.
ax
2
+ (4a
2
– 3b)x- 12ab = 0
Solution:
Question 20.
2x
2
+ ax – a
2
= 0
Solution:
Question 21.
Solution:
x
2
= 16
x = ±4
Question 22.
Solution:
Question 23.
Solution:
Question 24.
Solution:
Roots are 4, \(\frac { -2 }{ 9 }\)
Question 25.
Solution:
Question 26.
Solution:
Question 27.
Solution:
Question 28.
Solution:
Question 29.
Solution:
Question 30.
Solution:
Question 31.
Solution:
Question 32.
Solution:
Question 33.
Solution:
Question 34.
Solution:
Question 35.
Solution:
Question 36.
Solution:
Question 37.
Solution:
Question 38.
Solution:
Question 39.
Solution:
Question 40.
Solution:
Question 41.
x² – (√2 + 1) x + √2 = 0
Solution:
Question 42.
3x² – 2√6x + 2 = 0 [NCERT, CBSE 2010]
Solution:
Question 43.
√2 x² + 7x + 5√2 = 0
Solution:
Question 44.
\(\frac { m }{ n }\) x² + \(\frac { n }{ m }\) = 1 – 2x
Solution:
Question 45.
Solution:
Question 46.
Solution:
Question 47.
Solution:
Question 48.
Solution:
Question 49.
Solution:
Question 50.
x² + 2ab = (2a + b) x
Solution:
Question 51.
(a + b)
2
x² – 4abx – (a – b)2 = 0
Solution:
Question 52.
a (x² + 1) – x (a² + 1) = 0
Solution:
Question 53.
x² – x – a (a + 1) = 0
Solution:
Question 54.
x² + (a + \(\frac { 1 }{ a }\)) x + 1 = 0
Solution:
Question 55.
abx² + (b² – ac) x – bc = 0 (C.B.S.E. 2005)
Solution:
Question 56.
a²b²x² + b²x – a²x – 1 = 0 (C.B.S.E. 2005)
Solution:
Question 57.
Solution:
Question 58.
Solution:
Question 59.
Solution:
⇒ x = 0
x = 0, -7
Question 60.
Solution:
Question 61.
Solution:
Question 62.
Solution:
Exercise 8.3
Solution 30:
RD Sharma Class 10 Solutions
- Chapter 8 Quadratic Equations Ex 8.1
- Chapter 8 Quadratic Equations Ex 8.2
- Chapter 8 Quadratic Equations Ex 8.3
- Chapter 8 Quadratic Equations Ex 8.4
- Chapter 8 Quadratic Equations Ex 8.5
- Chapter 8 Quadratic Equations Ex 8.6
- Chapter 8 Quadratic Equations Ex 8.7
- Chapter 8 Quadratic Equations Ex 8.8
- Chapter 8 Quadratic Equations Ex 8.9
- Chapter 8 Quadratic Equations Ex 8.10
- Chapter 8 Quadratic Equations Ex 8.11
- Chapter 8 Quadratic Equations Ex 8.12
- Chapter 8 Quadratic Equations Ex 8.13