Rational Numbers Class 7 Extra Questions Maths Chapter 9

Rational Numbers Class 7 Extra Questions Maths Chapter 9

Extra Questions for Class 7 Maths Chapter 9 Rational Numbers

Rational Numbers Class 7 Extra Questions Very Short Answer Type

Question 1.
Find three rational numbers equivalent to each of the following rational numbers.
(i) $\frac{-2}{5}$
(ii) $\frac{3}{7}$
Solution:

Question 2.
Reduce the following rational numbers in standard form.
(i) $\frac{35}{-15}$
(ii) $\frac{-36}{-216}$
Solution:

Question 3.
Represent $\frac{3}{2}$ and $\frac{-3}{4}$ on number lines.
Solution:

Question 4.
Which of the following rational numbers is greater?
(i) $\frac{3}{4}$, $\frac{1}{2}$
(ii) $\frac{-3}{2}$, $\frac{-3}{4}$
Solution:

Question 5.
Find the sum of

Solution:

Question 6.
Subtract:

Solution:

Question 7.
Find the product:

Solution:

Rational Numbers Class 7 Extra Questions Short Answer Type

Question 8.
If the product of two rational numbers is $\frac{-9}{16}$ and one of them is $\frac{-4}{15}$, find the other number.
Solution:
Let the required rational number be x.

Question 9.
Arrange the following rational numbers in ascending order.

Solution:

Question 10.
Insert five rational numbers between:

Solution:

Rational Numbers Class 7 Extra Questions Long Answer Type

Question 11.
Evaluate the following:

Solution:

Question 12.
Subtract the sum of $\frac{-5}{6}$ and -1$\frac{3}{5}$ from the sum 2$\frac{2}{3}$ and -6$\frac{2}{5}$.
Solution:

Question 13.

Solution:
We have

Question 14.
Divide the sum of -2$\frac{15}{17}$ and 3$\frac{5}{34}$ by their difference.
Solution:

Question 15.
During a festival sale, the cost of an object is ₹ 870 on which 20% is off. The same object is available at other shops for ₹ 975 with a discount of 6$\frac{2}{3}$ %. Which is a better deal and by how much?
Solution:
The cost of the object = ₹ 870
Discount = 20% of ₹ 870 = $\frac{20}{100}$ × 870 = ₹ 174
Selling price = ₹ 870 – ₹ 174 = ₹ 696
The same object is available at other shop = ₹ 975

Selling price = ₹ 975 – ₹ 65 = ₹ 910
Since ₹ 910 > ₹ 696
Hence, deal at first shop is better and by ₹ 910 – ₹ 696 = ₹ 214

Rational Numbers Class 7 Extra Questions Higher Order Thinking Skills (HOTS) Type

Question 16.
Simplify:
21.5 ÷ 5 – $\frac{1}{5}$ of (20.5 – 5.5) + 0.5 × 8.5
Solution:
Using BODMAS rule, we have
21.5 ÷ 5 – $\frac{1}{5}$ of (20.5 – 5.5) + 0.5 × 8.5
= 21.5 ÷ 5 – $\frac{1}{5}$ of 15 + 0.5 × 8.5
= 21.5 × $\frac{1}{5}$ – $\frac{1}{5}$ × 15 + 0.5 × 8.5
= 4.3 – 3 + 4.25
= 4.3 + 4.25 – 3
= 8.55 – 3
= 5.55

Question 17.
Simplify:

Solution:
Using BODMAS rule, we have
2.3 – [1.89 – {3.6 – (2.7 – 0.77)}]
= 2.3 – [1.89 – {3.6 – 1.93}]
= 2.3 – [1.89 – 1.67]
= 2.3 – 0.22
= 2.08

Question 18.

Solution:
Using BODMAS rule, we have

Extra Questions for Class 7 Maths

NCERT Solutions for Class 7 Maths

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