NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are part of Class 11 Physics NCERT Solutions . Here we have given NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics.

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics

Topics and Subtopics in NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics :

Section Name	Topic Name
12	Thermodynamics
12.1	Introduction
12.2	Thermal equilibrium
12.3	Zeroth law of thermodynamics
12.4	Heat, internal energy and work
12.5	First law of thermodynamics
12.6	Specific heat capacity
12.7	Thermodynamic state  variables and equation of state
12.8	Thermodynamic processes
12.9	Heat engines
12.10	Refrigerators and heat pumps
12.11	Second law of thermodynamics
12.12	Reversible and irreversible processes
12.13	Carnot engine

QUESTIONS FROM TEXTBOOK

Question 12. 1 A geyser heats water flowing at the rate of 3.0 litres per minute from 2 7°C to 77°C. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 x 10 ⁴ J/g?
Answer: Volume of water heated = 3.0 litre per minute Mass of water heated, m = 3000 g per minute Increase in temperature,

Question 12. 2 What amount of heat must be supplied to 2.0 x 10 ^-2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? (Molecular mass of N ₂ = 28; R = 8.3 J mol ^-1 K ^-1 .)
Answer:

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Question 12. 3 Explain why
(a) Two bodies at different temperatures T ₁ and T ₂ , if brought in thermal contact do not necessarily settle to the mean temperature (T ₁ + T ₂ )/2 ?
(b) The coolant in a chemical or nuclear plant (i.e., the liquid used to prevent different parts of a plant from getting too hot) should have high specific heat. Comment.
(c) Air pressure in a car tyre increases during driving. Why?
(d) The climate of a harbour town is more temperate (i.e., without extremes of heat and cold) than that of a town in a desert at the same latitude. Why?
Answer: (a) In thermal contact, heat flows from the body at higher temperature to the body at lower temperature till temperatures become equal. The final temperature can be the mean temperature (T ₁ + T ₂ )/2 only when thermal capacities of the two bodies are equal.
(b) This is because heat absorbed by a substance is directly proportional to the specific heat of the substance.
(c) When car is driven, some work is being done on types in order to overcome dissipative forces of friction and air resistance etc. This work done is transformed into heat, due to which temperature of the car types increases.
(d) The climate of a harbour town is more temperate (neither too hot nor too cool) due to formation of sea breeze at day time and land breeze at night time as already explained in Chapter 11.

Question 12. 4 A cylinder with a movable piston contains 3 moles of hydrogen at standard temperature and pressure. The walls of the cylinder are made of a heat insulator, and the piston is insulated by having a pile of sand on it. By what factor does the pressure of the gas increase if the gas is compressed to half its original volume?
Answer:

Question 12. 5 In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J)
Answer:

Question 12. 6 Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completey evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following:
(a) What is the final pressure of the gas in A and B ?
(b) What is the change in internal energy of the gas?
(c) What is the change in the temperature of the gas?
(d) Do the intermediate states of the system (before settling to the final equilibrium state) lie of its P-V-T Surface?
Answer: (a) Since the final temperature and initial temperature remain the same,

(b) Since the temperature of the system remains unchanged, change in internal energy is zero.
(c) The system being thermally insulated, there is no change in temperature (because of free expansion)
(d) The expansion is a free expansion. Therefore, the intermediate states are non equilibrium states and the gas equation is not satisfied in these states. As a result, the gas can not return to an equilibrium state which lie on the P-V-T surface.

Question 12. 7 A steam engine delivers 5.4 x 10 ⁸ J of work per minute and services 3.6 x 10 ⁹ J of heat per minute from its boiler. What is the efficiency of the engine? How much heat is wasted per minute?
Answer:

Question 12. 8 An electric heater supplies heat to a system at a rate of 100 W. If system performs work at a rate of 75 Joules per second. At what rate is the internal energy increasing?
Answer:

Question 12. 9 A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Fig.Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F.
Answer:

Question 12. 10 A refrigerator is to maintain eatables kept inside at 9 °C, if room temperature is 36 °C. Calculate the coefficient of performance.
Answer:

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